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{{Calculus}} |
{{Calculus}} |
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In [[mathematics]], '''trigonometric substitution''' is the substitution of trigonometric functions for other expressions. One may use the [[trigonometric identity|trigonometric identities]] to simplify certain [[integral]]s containing |
In [[mathematics]], '''trigonometric substitution''' is the substitution of trigonometric functions for other expressions. One may use the [[trigonometric identity|trigonometric identities]] to simplify certain [[integral]]s containing radical expressions: |
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:<math> |
:<math>\sqrt{a^2-x^2}\ \Rightarrow \text{ let } x=a \sin(\theta) \text{ and use } 1-\sin^2(\theta) = \cos^2(\theta)</math> |
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:<math> |
:<math>\sqrt{a^2+x^2}\ \Rightarrow \text{ let } x=a \tan(\theta) \text{ and use } 1+\tan^2(\theta) = \sec^2(\theta)</math> |
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:<math>\ |
:<math>\sqrt{x^2-a^2}\ \Rightarrow \text{ let } x=a \sec(\theta) \text{ and use } \sec^2(\theta)-1 = \tan^2(\theta)</math> |
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In the expression ''a''<sup>2</sup> − ''x''<sup>2</sup>, the substitution of ''a'' sin(θ) for ''x'' makes it possible to use the identity 1 − sin<sup>2</sup>θ = cos<sup>2</sup>θ. |
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In the expression ''a''<sup>2</sup> + ''x''<sup>2</sup>, the substitution of ''a'' tan(θ) for ''x'' makes it possible to use the identity tan<sup>2</sup>θ + 1 = sec<sup>2</sup>θ. |
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Similarly, in ''x''<sup>2</sup> − ''a''<sup>2</sup>, the substitution of ''a'' sec(θ) for ''x'' makes it possible to use the identity sec<sup>2</sup>θ − 1 = tan<sup>2</sup>θ. |
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==Examples== |
==Examples== |
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:<math>\int\frac{dx}{\sqrt{a^2-x^2}}</math> |
:<math>\int\frac{dx}{\sqrt{a^2-x^2}}</math> |
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we may use |
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:<math>x=a\sin(\theta)\ \ \mbox{so}\ \mbox{that}\ \arcsin(x/a)=\theta,</math> |
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:<math>dx=a\cos(\theta)\,d\theta,</math> |
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:<math> |
:<math>x=a\sin(\theta)\ \Rightarrow\ \theta=\arcsin\left(\frac{x}{a}\right), dx=a\cos(\theta)\,d\theta</math> |
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so that the integral becomes |
so that the integral becomes |
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:<math>\int\frac{dx}{\sqrt{a^2-x^2}}=\int\frac{a\cos(\theta)\,d\theta}{\sqrt{a^2\cos^2(\theta)}} |
:<math>\int\frac{dx}{\sqrt{a^2-x^2}} = \int\frac{a\cos(\theta)\,d\theta}{\sqrt{a^2-a^2\sin^2(\theta)}} = \int\frac{a\cos(\theta)\,d\theta}{\sqrt{a^2(1-\sin^2(\theta))}} =</math> |
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=\int d\theta=\theta+C=\arcsin(x |
:<math>\int\frac{a\cos(\theta)\,d\theta}{\sqrt{a^2\cos^2(\theta)}} = \int d\theta=\theta+C=\arcsin\left(\frac{x}{a}\right)+C</math> |
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Note that the above step requires that ''a'' > 0 and cos(''θ'') > 0; we can choose the ''a'' to be the positive square root of ''a''<sup>2</sup>; and we impose the restriction on ''θ'' to be −π/2 < ''θ'' < π/2 by using the [[arcsin]] function. |
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For a definite integral, one must figure out how the bounds of integration change. For example, as ''x'' goes from 0 to ''a''/2, then sin(θ) goes from 0 to 1/2, so θ goes from 0 to π/6. Then we have |
For a definite integral, one must figure out how the bounds of integration change. For example, as ''x'' goes from 0 to ''a''/2, then sin(θ) goes from 0 to 1/2, so θ goes from 0 to π/6. Then we have |
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=\int_0^{\pi/6}d\theta=\frac{\pi}{6}.</math> |
=\int_0^{\pi/6}d\theta=\frac{\pi}{6}.</math> |
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Some care is needed when picking the bounds. The integration above requires that −π/2 < ''θ'' < π/2, so ''θ'' going from 0 to π/6 is the only choice. If we had missed this restriction, we might have picked ''θ'' to go from π to 5π/6, which would result in the negative of the result. |
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===Integrals containing ''a''<sup>2</sup> + ''x''<sup>2</sup>=== |
===Integrals containing ''a''<sup>2</sup> + ''x''<sup>2</sup>=== |
Revision as of 18:43, 28 February 2008
Part of a series of articles about |
Calculus |
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In mathematics, trigonometric substitution is the substitution of trigonometric functions for other expressions. One may use the trigonometric identities to simplify certain integrals containing radical expressions:
Examples
Integrals containing a2 − x2
In the integral
we may use
so that the integral becomes
Note that the above step requires that a > 0 and cos(θ) > 0; we can choose the a to be the positive square root of a2; and we impose the restriction on θ to be −π/2 < θ < π/2 by using the arcsin function.
For a definite integral, one must figure out how the bounds of integration change. For example, as x goes from 0 to a/2, then sin(θ) goes from 0 to 1/2, so θ goes from 0 to π/6. Then we have
Some care is needed when picking the bounds. The integration above requires that −π/2 < θ < π/2, so θ going from 0 to π/6 is the only choice. If we had missed this restriction, we might have picked θ to go from π to 5π/6, which would result in the negative of the result.
Integrals containing a2 + x2
In the integral
one may write
so that the integral becomes
(provided a > 0).
Integrals containing x2 − a2
Integrals like
should be done by partial fractions rather than trigonometric substitutions.
The integral
can be done by the substitution
This will involve the integral of secant cubed.
Substitutions that eliminate trigonometric functions
Substitution can be used to remove trigonometric functions. For instance,
(but be careful with the signs)